Posted by ESPN.com's Tim Graham
Three teams are tied for the AFC East lead with three games to go.
Who has the best chance of finishing on top?
The Dolphins and Jets meet Dec. 28 in the season finale. The Patriots already have played them, losing at home and winning on the road against each.
Miami has the easiest remaining schedule based on records and ease of travel. Miami's opponents are a combined 15-24 with one game at home and two on the road, but its farthest trip is to hospitable Kansas City.
The Jets' opponents are an aggregate 16-23. While they're the only club among the top three with two home games left, the travel is daunting. They returned from Sunday's game at San Francisco to play at home next, will venture to Seattle (they're 0-3 in the Pacific Time Zone) and then head back home to finish with the Dolphins.
The Patriots have the least control. Their only remaining divisional game is against the Buffalo Bills, who were eliminated from contention Sunday. The Patriots are staying out West in between their games at Seattle and Oakland. They'll face opponents with a combined 16-23 record, but will log some miles.
Miami Dolphins: Have won six of their past seven games.
Dec. 14 vs. San Francisco 49ers (5-8)
Dec. 21 at Kansas City Chiefs (2-11)
Dec. 28 at New York Jets (8-5)
New England Patriots: Haven't won consecutive games since Weeks 7 and 8, and haven't won three in a row all year.
New York Jets: Have dropped two in a row after winning six out of seven.
Dec. 14 vs. Buffalo Bills (6-7)
Dec. 21 at Seattle Seahawks (2-11)
Dec. 28 vs. Miami Dolphins (8-5)